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When \(a \ne 0\), there are two solutions to \(ax^2 + bx + c = 0\) and they are

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

\begin{align} \sqrt{37} & = \sqrt{\frac{73^2-1}{12^2}}
& = \sqrt{\frac{73^2}{12^2}\cdot\frac{73^2-1}{73^2}} \
\end{align} mathjax
mathjax documents